The bottom answer is wrong; it's prime because it cannot be divisible by anything except for itself and one.
Please give me Brainliest!!
Answer:
No, it is not a right triangle.
Step-by-step explanation:
The simplest way to determine is testing out the numbers with Pythagorian theorem.
If it complies with the theorem, it is a right triangle.
let's assume c = 28, b = 21, and a = 20
the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.
According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.
check:
c^2 = 28^2 = 784
a^2 + b^2 = 21^2 + 20^2 = 841
because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.
12300=X[((1-(1+(0.072/12)^(-12*8))/(0.072/12)]
Solve for x
X=168.92
Her check register will have a surplus of 64 dollars compared to her actual balance.
example
100 +32 = 132 (incorrect)
100 -32 = 68 (correct)
132 -68 = 64 surplus
