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Crank
3 years ago
7

Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the

same number of pencils and the same number of notebooks.​
Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

The maximum number of packages that can be made  with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

<em>To find the G.C.F., we will list down the prime factors of each.</em>

48=2\times 2\times 2\times 2\times 3

30=2\times 3\times 5

We find that the G.C.F. = 2\times 3 = 6

Thus, the maximum number of packages that can be made  with each package have same number of each item is = 6

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Step-by-step explanation:

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Now, you plug in and solve.

V=(3.14)(7.2^{2})(7.4)\\V=(3.14)(51.84)(7.4)\\V=(162.7776)(7.4)\\V=1204.55424\\rounded:\\V=1204.6

Then, you find the volume of the dome.

Here's the formula:

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Now, you just plug in and solve.

V=(\frac{2}{3})(\pi)(r^{3})\\V=(\frac{2}{3})(3.14)(7.2^{3})\\V=(\frac{2}{3})(3.14)(373.248)\\V=(2.093)(373.248)\\V=781.208064\\rounded:\\V=781.2

Finally, you add them together, and there's your answer!

1204.6+781.2=1985.8

Hope this helped!

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