In short, (h o g)(a) is just h( g(a) ).

so what we can do is simply get g(a) first and then plug that in h(x).

$\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
\\\\\\
h(~~2a~~)=(2^2a^2)+4\implies h(~~2a~~)=4a^2+4$

8 0

4 years ago

A gardener has a circular flower bed with a radius of 17 feet. If she wants to make a square flower bed with the same area as th

mylen [45]

We know that

• The radius is 17 feet.

First, we find the circular area

$\begin{gathered} A=\pi(r)^2 \\ A=3.14(14)^2\approx3.14\cdot196\approx615.44ft^2 \end{gathered}$

This means the square flower bed will have an area of 615.44 square feet. So, we find its sides with the formula for squared areas

$\begin{gathered} A=l^2 \\ 615.44=l^2 \\ l=\sqrt{615.44}\approx24.808 \end{gathered}$ <h2>Therefore, the bed should have sides of 24.808 feet, approximately.</h2>

8 0

1 year ago