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kramer
3 years ago
11

Convert 3/16 inch to a decimal

Mathematics
1 answer:
vfiekz [6]3 years ago
4 0
The answer is 0.1875
idk if this helped the tiniest bit but i tried
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15 / √31 - 4
NeX [460]

Answer:

\frac{15}{ \sqrt{31} - 4}} = \sqrt{31} + 4

Step-by-step explanation:

\frac{15}{\sqrt{31} - 4}\\\\=\frac{15}{\sqrt{31} - 4} \times \frac{\sqrt{31} + 4}{\sqrt{31}+ 4} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   [  \ rationalizing \ the \ denominator \ ]\\\\=\frac{15( \sqrt{31} + 4 )}{(\sqrt{31})^2 - (4)^2}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ [ \ (a-b)(a+b) = a^2 - b^2 \ ]\\\\=\frac{15 ( \sqrt{31} + 4)}{31 - 16}\\\\=\frac{15 (\sqrt{31} + 4)}{15}\\\\= \sqrt{31} + 4

6 0
2 years ago
Find the sum of (-4 + 1) and (10 – 5:).
ANTONII [103]

Answer:

6 - 4i

Step-by-step explanation:

-4 + i = 10 - 5i

<u>+4       +4      </u>

i = 14 + 5i

<u>-5i      -5i      </u>

-4i = 14

i = -3.5

4 0
3 years ago
Read 2 more answers
The first three cards dealt from a
mart [117]
There are four aces, 12 face cards and 4 7s in a standard 52 card deck. The probability of getting an ace on the first draw is 4/52 or 1/13. For the second draw there are now 51 cards in the deck (assuming the draws are without replacement), so the probability of getting a face card is 12/51. Given an ace and a face card on the first two draws, the probability of a 7 on the third draw is 4/50 or 2/25. The probability of getting all three is 1/13*12/51*2/25.
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Related Questions (More Answers Below)
5 0
3 years ago
Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a
geniusboy [140]
(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}

The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.
7 0
3 years ago
What if I can't answer the questions you give me​
Leviafan [203]

Answer:

can u help answer mine

Step-by-step explanation:

6 0
3 years ago
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