For this question I would need the money amount what minimum might possibly be? please and thank you
Answer:
60 kilometers
Step-by-step explanation:
<em>1</em><em> </em><em>centimeter</em><em> </em><em>=</em><em> </em><em>3</em><em> </em><em>kilometers</em><em> </em>
<em>2</em><em>0</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em> </em>
Think of sea level as 0 on number line
-13 + 6 - 15
<h3>
Answer: 15x^(7/3) - 8x^(7/4) + x + 9000</h3>
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Explanation:
If you know the cost function C(x), to find the marginal cost, we apply the derivative.
Marginal cost = derivative of cost function
Marginal cost = C ' (x)
Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.
![\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\](https://tex.z-dn.net/?f=%5Ctext%7BCost%7D%20%3D%20%5Ctext%7Bantiderivative%20of%20marginal%20cost%7D%5C%5C%5C%5C%5Cdisplaystyle%20C%28x%29%20%3D%20%5Cint%20%5Cleft%2835x%5E%7B4%2F3%7D%20-%2014x%5E%7B3%2F4%7D%20%2B%201%5Cright%29dx%5C%5C%5C%5C)
![C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\](https://tex.z-dn.net/?f=C%28x%29%20%3D%20%5Cfrac%7B1%7D%7B1%2B4%2F3%7D%2A35x%5E%7B4%2F3%2B1%7D%20-%20%5Cfrac%7B1%7D%7B1%2B3%2F4%7D%2A14x%5E%7B3%2F4%2B1%7D%20%2B%20x%20%2B%20D%5C%5C%5C%5CC%28x%29%20%3D%20%5Cfrac%7B1%7D%7B7%2F3%7D%2A35x%5E%7B7%2F3%7D%20-%20%5Cfrac%7B1%7D%7B7%2F4%7D%2A14x%5E%7B7%2F4%7D%20%2B%20x%20%2B%20D%5C%5C%5C%5CC%28x%29%20%3D%20%5Cfrac%7B3%7D%7B7%7D%2A35x%5E%7B7%2F3%7D%20-%20%5Cfrac%7B4%7D%7B7%7D%2A14x%5E%7B7%2F4%7D%20%2B%20x%20%2B%20D%5C%5C%5C%5CC%28x%29%20%3D%2015x%5E%7B7%2F3%7D%20-%208x%5E%7B7%2F4%7D%20%2B%20x%20%2B%20D%5C%5C%5C%5C)
D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).
To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.
Therefore, we go from this
![C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\](https://tex.z-dn.net/?f=C%28x%29%20%3D%2015x%5E%7B7%2F3%7D%20-%208x%5E%7B7%2F4%7D%20%2B%20x%20%2B%20D%5C%5C%5C%5C)
to this
![C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\](https://tex.z-dn.net/?f=C%28x%29%20%3D%2015x%5E%7B7%2F3%7D%20-%208x%5E%7B7%2F4%7D%20%2B%20x%20%2B%209000%5C%5C%5C%5C)
which is the final answer.