The sum of two numbers is 15. One number is three less than the other. Find the numbers.
1 answer:
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The inequality would look like this:
-2 (3x + 2)
-6x-4
To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis
-2 x 3x = -6x
-2 x 2 = -4
-6x -4-6x-4
Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality
0x -4-4
Next perform the opposite operation by adding 4 on both sides of the inequality
0x 0
Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)
-2 (3x + 2)
To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis
-2 x 3x = -6x
-2 x 2 = -4
-6x -4
Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality
0x -4
Next perform the opposite operation by adding 4 on both sides of the inequality
0x
Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)