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wariber [46]
3 years ago
9

Solve the equation -3(y-5)=24

Mathematics
1 answer:
ioda3 years ago
3 0
-3(y-5) = 24...distribute through the parenthesis
-3y + 15 = 24....subtract 15 from both sides
-3y = 24 - 15
-3y = 9...divide both sides by -3
y = 9/-3
y = -3
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Use a proportion if two cassettes cost $14.50 How much will 15 cost
aev [14]
Cost/(number of cassettes) = $14.50/2 = x/15

Multiply by 15 to solve
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15 cassettes will cost $108.75.
8 0
3 years ago
At a garden shop, a customer buys 5 geraniums and 4 lilies for $48. Another customer pays $58 for 4 geraniums and 6 lilies. Writ
masha68 [24]

Answer:

A lily costs $7 and a geranium $4.

Step-by-step explanation:

From the question, we can write two equations. let the number of lilies be l and the number of geraniums be g, then:

5 g + 4 l = 48

4 g + 6 l = 58

Multiply the first equation by 4 and the second by 5, the number of lilies in the other gives:

20 g + 16 l = 192

20 g + 30 l = 290

Subtract the first equation from the second gives:

14 l = 98  which dividing by 14 gives  l = 7

Substituting the value  l = 7  in the first equation gives:

5 g + 28 = 48

Subtract 20 from both sides gives:

5 g = 20  divide by 5 gives  g = 4

So, a lily costs $7 and a geranium costs $4.

7 0
2 years ago
Sorry this is the last one! Help for brainliest answer
laila [671]

Answer:

5, 6, 9, 15

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6 0
3 years ago
Read 2 more answers
Numerical coefficient of the term x over 7
Over [174]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
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