Answer:
x^2 + (y+1)^2 = 10^2
Step-by-step explanation:
Centre (p,q) = (0, -1)
radius, r = 10
General Equation of a circle
(x-p)^2 + (y-q)^2 = r^2
(x-0)^2 + (y- -1)^2 = 10^2
x^2 + (y+1)^2 = 10^2
Answer:
ccccc
Step-by-step explanation:
Simple, plug n chug...
t=2
u=-8
v=-0.5
Now, plug in what you have,
Now,
2-16=-14
Thus, your answer, -14.
You could interpret them as system of equation and answer the question easily
from A
-4x + y + x + w =1
write in same form from A
as this system has five variables and four of them are unknowns it means the unique solution is not possible
So, det (A) = 0
Okay so basically domain =input and range =output. you can never have a negative number underneath the square root sign because it will make the answer imaginary (i), unless you are on that concept. Therefore the range is any number greater than 0. -> all real numbers greater than or = 0
for the range if you input 0 as x you will get -5, so any number you input after 0 will be greater than -5. so range is all real numbers greater than or equal to -5.
