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3 years ago

1/4 is to 1 1/4 as 2 is to b

Mathematics

1 answer:

kodGreya [7K]3 years ago

7 0

Answer:

b=22

Step-by-step explanation:

11/4 divided by 1/4 equals 11. 11*2 =22

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A train heads south out of Bloomington an hour after a northbound train

ahrayia [7]

9514 1404 393

Answer:

northbound: 2.5 hours
southbound: 1.5 hours

Step-by-step explanation:

When the second train leaves the station, the trains are already 63 miles apart. The rate of increase of their separation is (57 +63) = 120 miles per hour. The remaining 243-63 = 180 miles of separation will be achieved in ...

(180 mi)/(120 mi/h) = 1.5 h

The northbound train will have traveled 2.5 hours; the southbound train will have traveled 1.5 hours when the trains are 243 miles apart.

7 0

3 years ago

Helppppppppppppppppppppppppp

Wewaii [24]

Answer:

Radius: 8

Circumference: 50.27

πr^2 = Area of circle

201.06 = πr^2

divide by pi

201.06 / π = 63.9993857161 = 64

64 = r^2

Square root both sides to get radius.

$\sqrt{64}$ = 8

r = 8

Circumference = π x diameter

Diameter = 2 x radius

Circumference = π x 16 = 50.2654824574 = 50.27

8 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$