A) Variance = 10.24
B) Standard Deviation = 3.2
One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.
TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²
0 - 0.9 43 0.45 -3 9 -129 387
1.0 - 1.9 17 1.45 -2 4 -34 68
2.0 - 2.9 19 2.45 -1 1 -19 19
3.0 - 3.9 18 3.45 0 0 0 0
4.0 - 4.9 14 4.45 1 1 14 14
5.0 -5.9 16 5.45 2 4 32 64
∑f = 127
∑fd = -136
∑fd² = 552
![d = \frac{x - 3.45}{1}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bx%20-%203.45%7D%7B1%7D)
Standard Deviation = ![\sqrt \frac{fd^{2} }{N} - \sqrt \frac{(fd)^{2} }{N} * i](https://tex.z-dn.net/?f=%5Csqrt%20%5Cfrac%7Bfd%5E%7B2%7D%20%7D%7BN%7D%20-%20%5Csqrt%20%5Cfrac%7B%28fd%29%5E%7B2%7D%20%7D%7BN%7D%20%2A%20i)
![\sqrt \frac{552}{127} -\sqrt (\frac{-136}{127})^{2} * 1](https://tex.z-dn.net/?f=%5Csqrt%20%5Cfrac%7B552%7D%7B127%7D%20-%5Csqrt%20%28%5Cfrac%7B-136%7D%7B127%7D%29%5E%7B2%7D%20%20%20%2A%201)
√4.35 - √1.15
Standard Deviation = 3.2
(SD)² = (3.2)² = 10.24
Variance = 10.24
To know more about standard deviation, refer to this link :
brainly.com/question/12402189
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So, when doing this kind of problems, the first thing that we would want to do is to add up (all) the numbers first, and by doing this, it would look like the following:
![5+5+ 8+10=28](https://tex.z-dn.net/?f=5%2B5%2B%208%2B10%3D28)
Then, we would then divide it by how many numbers they are.
![\boxed{28\div4} \ =7](https://tex.z-dn.net/?f=%5Cboxed%7B28%5Cdiv4%7D%20%5C%20%3D7)
Your answer:
7
Answer:
truee
Step-by-step explanation:
i had this answer on my test and if i dont get it right sorry
9514 1404 393
Answer:
n = 3
Step-by-step explanation:
In order for 3 × 3 = 9 to be a factor of both numbers, we must have ...
n = 3
•<span>75% = 0.75
•</span><span>450 ÷ 0.75 = 600
•</span><span>450 is 75% 0f 600
There are the steps that I used to get that </span><span>450 is 75% 0f 600</span>