Answer:
The Quotient Property.
Step-by-step explanation:
Since all three logarithms have the same base (base-5), and you are subtracting 6 and 3, to solve this all you need to do is 6 / 3 because of the Quotient Property.
You aren't multiplying anything, so you wouldn't use the Product Property.
You are not messing around with powers, so you wouldn't use the Power Property.
And you aren't using addition or multiplication, so you wouldn't use the Commutative Property.
Hope this helps!
Answer:
a. f(-1)=12
b. f(2t)=16t²-6t+5
c. f(t-2)=4t²-19t+27
Step-by-step explanation:
For a, b, c, we are given an input. We plug that into f(x) to find our answers.
a. f(-1)=12
f(-1)=4(-1)²-3(-1)+5
f(-1)=4+3+5
f(-1)=12
-------------------------------------------------------------------------------------------------------------
b. f(2t)=16t²-6t+5
f(2t)=4(2t)²-3(2t)+5
f(2t)=4(4t²)-6t+5
f(2t)=16t²-6t+5
-------------------------------------------------------------------------------------------------------------
c. f(t-2)=4t²-19t+27
f(t-2)=4(t-2)²-3(t-2)+5
f(t-2)=4(t²-4t+4)-3t+6+5
f(t-2)=4t²-16t+16-3t+6+5
f(t-2)=4t²-19t+27
<span>4 hundreds 13 tens 5 ones = 400+13*10+5
= 400+130+5
= 535</span>
Step-by-step explanation:
