F'(x) = 5sin(x) + 5x*cos(x) = 0.
<span>Then, setting f'(x) = 0 gives: </span>
<span>5sin(x) + 5x*cos(x) = 0 ==> tan(x) + x = 0. </span>
<span>Then, use Newton's Method to solve tan(x) + x = 0 on 0 <= x <= π. This solves to get x ≈ 2.028758. Using the Second Derivative Test, you can show that this gives a maximum. Therefore, the required maximum value is: </span>
<span>f(2.028758) = 2(2.028758)sin(2.028758) ≈ 3.639411........google told me this</span>
Greenwich , a town is England
B i think not really sure
Answer:
qualified
Explanation: just took the test on ed2020
