It's is true because 4 and 5are closer
Answer:
52
Step-by-step explanation:
We can write this out as an equation. Let's say that the teacher's age is x. Triple the teachers age plus the students age is 163, which can be written out as:
We want to isolate the variable, so subtract 7 from both sides. This gives us:
Finally, we divide both sides by 3, giving:
So the teacher is 52 years old.
Hope this helps!
X = 52 would be the answer you get.
Explanation you would divide both sides by 0.6 which leaves the x and by dividing 31.2 divided by 0.6 it gives you 52
Answer:
Step-by-step explanation:
1) ?
I can't see what that one given angle is .. but it's that mystery angle subtracted from 180 give the angle BOA then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of 180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90 to find the angle BAX
2) ( as we would read normally)
You're making this really tough on me.. I can just barely read the equations
I think it's 1+6x and 7x-3 . b/c they are the same length sides you can set those equal
1+6x = 7x -3
4+6x = 7x
4 = x
that worked out well :
for the tangent.. it's Tan(Ф)= Opp/ Adj
but I don't know which side they want to solve for.. I think you may have left off some of the instructions???? :/
ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.
1+6(4) = 25
or
7(4)-3=25
tangent is 25
3)
x-2 = 2x-10
x+8 = 2x
8 = x
again they made it work out easy :)
Then plug 8 into either equation to find the length of the tangent lines
8-2=10
tangent is 10
4) = 2) ??? they are the same question maybe you meant to put something else?
Answer:
6√2
Step-by-step explanation:
Given,
θ = 45
Opposite side = 6
To find : - Hypotenuse
Formula : -
sin θ = Opposite side / Hypotenuse
[ The value of sin 45 = 1 / √2 ]
sin 45 = 6 / Hypotenuse
1 / √2 = 6 / Hypotenuse
Cross multiply,
Hypotenuse = 6√2
