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3 years ago

Suppose the diameter of a circle is 6 units. What is its circumference?

Mathematics

1 answer:

Basile [38]3 years ago

6 0

C=2•pi• R
D=6 then the radius is 3
2•Pi•3 =18.85

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A small school has 27 boys .if the ratio of boys to girls is 9:4, how many students are their together

Sauron [17]

9:4, so for every 9 boys there are 4 girls. 27 is 3 times 9, so multiply 4 with 3, you get 12. Count them up and BOOM, 39

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3 years ago

Given the following system of equations, identify the type of system.

DanielleElmas [232]

Step-by-step explanation:

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3 years ago

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A plane traveled 580 miles to Ankara and back. the trip there was with the wind. It took 5 hours. The trip back was into the win

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3 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

bernite is selling candy bars for a school fundraiser. the school paid $20 for a box of 15 king size candy bars and bernite sell

NikAS [45]

The school originally used $20 for the purchase of the candy.
Use the formula Y=2x to find how much money is made (y) from the number of candy bars (x)
Sub in the 15 bars for t
Y=2(15)
Y=30
Therefore the school made $10, because they earned an extra $10 in comparison to the amount they bought the candy bars for, which was $20.
Hope this helps!

6 0

3 years ago