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juin [17]
2 years ago
10

Target Costing

Mathematics
1 answer:
Lynna [10]2 years ago
6 0

The target cost for Model J20 is $2000.

The required cost reduction is $30.

The total saving will be $30.3.

<h3>How to compute the cost?</h3>

The target cost will be:

= Sales price - (100% × Target cost)

= 400 - (100% × Y)

Y + Y = 400

2Y = 400

Y = 400/2 = 200

Target cost = $200

Therefore, the target cost is $200.

The required cost reduction will be:

= $230 - $200

= $30

The required cost reduction is $30.

The three engineering improvements together will be:

Direct labor reduction = 7.5

Additional inspection = 17

Injection molding = 5.8

Total savings = 30.3

The total savings is $30.3.

Learn more about cost on:

brainly.com/question/10705492

#SPJ1

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Step-by-step explanation:

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The probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48 and of owning both is 0.45.
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Answer:

The probability that the middle school student owns a skateboard or a bicycle is 0.61.

Step-by-step explanation:

We are given that the probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48, and owning both is 0.45.

A middle school student is chosen at random.

Let the probability of student owning a skateboard = P(S) = 0.58

The probability of student owning a bicycle = P(B) = 0.48

The probability of student owning both = P(S \bigcap B) = 0.45

Now, the probability that the middle school student owns a skateboard or a bicycle is given by = P(S \bigcup B)

        P(S \bigcup B) = P(S) + P(B) - P(S \bigcap B)

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                      = 0.61

Hence, the probability that the middle school student owns a skateboard or a bicycle is 0.61.

4 0
3 years ago
Which is greater 7% or 7/10
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Answer: The first and last options are correct.

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Hope this helps :)

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3 years ago
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