Question

WILL GIVE BRAINLIEST... Find a polynomial, of degree 3, with integer coefficients that has zeros of x=2, x=-1 and Show all work and foil your answer.

Answer 1

Answer:

( x - 3i ) ( x + 3i )

 

= x^2 + 3xi - 3xi - 9i^2

 

= x^2 - 9 (-1)

 

= x^2 + 9

 

(x^2 + 9 ) ( x + 5 )

 

Now the left hand side is equal to the right hand side.

 

Good luck!

Step-by-step explanation:

Answer 2

Answer:

$x^3+2x^2-5x-6$

note this isn't the only possible answer; read below.

Step-by-step explanation:

For quadratic formulas when you foil the equation you can easily identify the root values by setting them equal to 0 and solving for X. Note that a quadratic is of 2 degree so you get 2 root values. Now, instead  of 2, you have 3.

So... they give you the zeros x=2 and x=-1, now add your own random x value.

(x-2)(x+1)(x+3)

Now you can foil it into a polynomial equation.