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Hunter-Best [27]
3 years ago
10

10 10 O A. (3,8) B. (6,5) O c. (5,6) O D. (8,3)

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

B.(6,5)

Step-by-step explanation:

because (6,5) ang sagot

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What is the lest comen demomator of 1/8 1/12 and 7/18
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72

Step-by-step explanation:

18*4

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8*9

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2. aubrey solves the equation x-4 = 4 - x and shows her work she found that x = 4 and x = 5 what mistake did she make what is th
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Answer: x doesn't equal four x would have to equal -5 because it cant before because it would be a zero and there would be no solution

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What inequality is 1/2x - 5 &gt; -7
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x/2 - 5 > - 7
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3 years ago
what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?
julsineya [31]

Answer:

\frac{\pi }{2} and \frac{3\pi }{2}

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\

Now we need to find when f'(x)=0 to find the critical values.

0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x

The critical values will be

\frac{\pi }{2} n for any integer n

between 0 and 2 pi, the critical values will be

0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)

We need to see if the second derivative is positive or negative to determine if it is a max or min.

f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\

Since the second derivative is negative at

\frac{\pi }{2} and \frac{3\pi }{2}

we know both of those are the x-values of maximums.

5 0
4 years ago
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