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noname [10]
3 years ago
5

Can someone please help me with #6!

Mathematics
1 answer:
Digiron [165]3 years ago
4 0
You have to find the area of each part and add them together.


There are three parts. The area of the first part is 6*12 which is 72. The next part is 6*6 which is 36. And the next part is 6*6*(1/3), I think. So the answer should be 120.
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A certain forest covers an area of
Nookie1986 [14]
Happy to help :)
after 1 yr- 3905.25 km2
2 yrs- approx. 3719.75 km2
3 yrs- approx. 3543.06 km2
4 yrs- approx. 3374.77 km2
5 yrs- approx. 3214.47 km2

The full decimal for the 5 yr mark is 3214.46557 km2 (not sure if you needed it)

To solve you would convert 4.75% into .0475 as a decimal, then subtract that from 1 (which acts as 100%) and you get .9525, then just multiply that by 4100 and each number that results from that ;)
7 0
3 years ago
Can someone pleaseeee tell me what these areee
Dima020 [189]

Question #9 - - 11/30

Question #10 - - 3/11

Question #8 - - 147/290

I really hope this helps. Good luck!

5 0
3 years ago
a commitee of 4 is chosen at random from a group of 5 married couples. what is the probability that the commitee includes no two
Inessa05 [86]

Answer:0.524

Step-by-step explanation:

Prob = 1 - ((5C2*5C2)/10C4)

=1- ((10*10)/210)

=1-0.476

= 0.524

3 0
4 years ago
Find the value of x in the<br> isosceles triangle shown below.<br> Help plzzzz
zysi [14]

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

{x}^{2}  +  {4}^{2}  =  \sqrt{20} {}^{2}

{x}^{2}  =  \sqrt{20} ^{2}   - 16

{x}^{2} = 20 - 16

x = 2

6 0
4 years ago
A rational number raised to a rational power can either be rational or irrational. For example, 4^( 1/ 2) is rational because 4
Lady bird [3.3K]

Answer:

Step-bThis is an interesting problem. To solve it I should find two irrational numbers r and s such that rs is rational.

I am not sure I am able to do that. However, I am confident that the following argument does solve the problem.

As we know, √2 is irrational. In particular, √2 is real and also positive. Then √2√2 is also real. Which means that it is either rational or irrational.

If it's rational, the problem is solved with r = √2 and s = √2.

Assume √2√2 is irrational. Let r = √2√2 and s = √2. Then rs = (√2√2)√2 = √2√22 = √22 = 2. Which is clearly rational.

Either way, we have a pair of irrational numbers r and s such that rs is rational. Or do we? If we do, which is that?

(There's an interesting related problem.)

Chris Reineke came up with an additional example. This one is more direct and constructive. Both log(4) and √10 are irrational. However

√10 log(4) = 10log(2) = 2.y-step explanation:

7 0
3 years ago
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