Find the value of x in the isosceles triangle shown below. Help plzzzz

Mathematics

1 answer:

zysi [14]4 years ago

6 0

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

${x}^{2} + {4}^{2} = \sqrt{20} {}^{2}$

${x}^{2} = \sqrt{20} ^{2} - 16$

${x}^{2} = 20 - 16$

$x = 2$

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Answer:

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Step-by-step explanation:

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A candy box is made from a piece of cardboard that measures 23 by 13 inches. Squares of equal size will be cut out of each corne

wolverine [178]

Answer:

2.67 inches.

Step-by-step explanation:

Assuming that we represent the size of the squares with the letter y, such that after the squares are being cut from each corner, the rectangular length of the box that is formed can now be ( 23 - 2y), the width to be (13 - 2y) and the height be (x).

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Now for the maximum volume:

dV/dy = 0

This implies that:

299y - 72y² + 4y³ = 299 - 144y + 12y² = 0

By using the quadratic formula; we have :

$= \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}$