Question

Find the value of x in the isosceles triangle shown below. Help plzzzz

Answer 1

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

${x}^{2} + {4}^{2} = \sqrt{20} {}^{2}$

${x}^{2} = \sqrt{20} ^{2} - 16$

${x}^{2} = 20 - 16$

$x = 2$