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FinnZ [79.3K]
3 years ago
10

Find the value of x in the isosceles triangle shown below. Help plzzzz

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

{x}^{2}  +  {4}^{2}  =  \sqrt{20} {}^{2}

{x}^{2}  =  \sqrt{20} ^{2}   - 16

{x}^{2} = 20 - 16

x = 2

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arsen [322]

The value of x is 36.

Solution:

Given angles of a triangle are 2x°, 2x° and x°.

To find the value of x:

<em>Sum of the all the angles of a triangle = 180°</em>

2x° + 2x° + x° = 180°

5x° = 180°

Divide by 5 on both sides of the equation.

x° = 36°

x = 36

The value of x is 36.

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