4 years ago

Find the value of x in the isosceles triangle shown below. Help plzzzz

Mathematics

1 answer:

zysi [14]4 years ago

6 0

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

${x}^{2} + {4}^{2} = \sqrt{20} {}^{2}$

${x}^{2} = \sqrt{20} ^{2} - 16$

${x}^{2} = 20 - 16$

$x = 2$

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