If f(x)=ln x and g(x)=e^x+1 find f(g(2))-g(f(e)) please help!!
1 answer:
Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
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Answer:
there would be 52 more girls I think
Step-by-step explanation:
let x = multiplier then
31x =number of boys
44x = number of girls
Boys + girls = 300
44x + 31x =300
75x = 300
x = 300/75
x = 4 is the multiplier
therefore:
44*4 = 176 girls
31*4 = 124 boys
dif = 52 more girls than boys
hope this helped :)
4+6+2+2+3+4+6+3=30
14/30 = male
16/30=female
6/30= female junior
6/30= 1/5=20%
Answer: 20%
Answer:
2) -81t² +16
Step-by-step explanation:
(9t -4)(-9t -4) = (9t x -9t) + (9t x -4) + (-4 x -9t) + (-4 x -4)
= -81t² - 36t + 36t + 16
= -81t² + 16
Solution: (2,8)
Using the elimination method set up the system of equations like:
y = x + 6
y = 3x + 2
Eliminate the x-variable by multiplying the top equation by -3
-3y = -3x -18
y = 3x + 2
Combine terms:
-2y = -16
-y = -8
y = 8
Plug in 8 to one of the first equations for y
8 = 3x + 2
6 = 3x
x = 2
Solution: (2,8)
