Answer:
tan A = -15/8.
Step-by-step explanation:
sin^2a = 1 - cos^2A
= 1 - (-8/17)^2
= 225/289
So sin A= 15/17
tan A = sin A / cos A
= 15/17 / -8/17
= 15/-8
= -15/8.
1. D
2. J
3. L
4. A
5. B
6. K
7. C
8. I
9. F
10. G
Radius = Center to Perimeter of Circle
Minor Arc = Arc that goes around less than 1/2 of circle
Major Arc = Arc that goes around more than 1/2 of circle
Chord = The straight line segment between 2 points on a circle
Secant = A line that passes through 2 points on a circle
Semicircle = 1/2 Circle
Tangent = Line that touches 1 point on a circle's perimeter
Central Angle = Angle with a vertex at the center of a circle
Inscribed Angle = Angle whose 3 points (vertex & 2 other points) are on the outside of the circle
Right Angle = Angle with 90 degree measure
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
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The "coefficient" of the "a" term is: " - 12" .
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The "constant" is: " 32 " .
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Explanation:
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Let: "a = x² + 4 " .
Given: (x² + 4)² + 32 = 12x² + 48 ;
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Factor: "12x² + 48" into " (x² + 4) " ;
"12x² + 48" = 12 (x² + 4) " ;
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Given: (x² + 4)² + 32 = 12x² + 48 ;
rewrite as; "a² + 32 = 12a " ;
Subtract "12a" from each side of the equation;
"a² + 32 - 12a = 12a - 12a ;
to get:
" a² - 12a + 32 = 0 " .
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The coefficient of the "a" term; that is:
The "coefficient" of " -12a" ; is: "- 12" .
The constant is: "32<span>" .
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Answer:
The answer is below
Step-by-step explanation:
a)Given that the length of fencing available is 400 yards. This means that the perimeter of the rectangle is 400 yards.
the perimeter of a rectangle is given as:
Perimeter = 2(length + width) = 2(l + w)
Hence;
400 = 2(l + w)
200 = l + w
l = 200 - w
The area of a rectangle is given as:
Area = length × width
Area = (200 - w) × w
Area = 200w - w²
b) For a quadratic equation y = ax² + bx + c. it has a maximum at x = -b/2a
Hence, for the area = 200w - w² a=-1, b = 200, the maximum width is at:
w = -b/2a = -200/2(-1) = -200/-2 = 100
A width of 100 yard has the largest area
c) l = 200 - w = 200 - 100 = 100 yards
Area = l × w = 100 × 100 = 10000 yd²
The maximum area is 10000 yd²