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professor190 [17]
3 years ago
9

Solve the absolute value equation algebraically: 3|2x - 3| + 2 = 3

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

3 |2x - 3|  = 1

3 |2x - 3|  = 1 \\ 6x - 9 = 1 \\ 6x = 10 \\ x =  \frac{10}{6}  = \frac{5}{3}

3 |2x - 3|  =  - 1 \\ 6x - 9 =  - 1 \\ 6x = 8 \\ x =  \frac{4}{3}

x =  \frac{5}{3} x =  \frac{4}{3}

I am sorry but I am not sure of this :(

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What x-value makes the set of ratios equivalent? Tiles 2 : 3 = 6 : x ,4 : 7 = x : 42 , 2x : 48 = 3 : 12, 12 : 15 = x : 20
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Step-by-step explanation:

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\frac{3}{12}[/tex] = \frac{2x}{48}12*4 = 48, we multiply top  and bottom of fraction by 4[tex]\frac{3*4}{12*4} = \frac{12}{48}

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15 * \frac{4}{3} = 20,

we multiply top  and bottom   by 4/3

 12 * \frac{4}{3} = 16

So value of x=16

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