Question

If an=24, which recursive formula could represent the sequence below? ...,24,88, 664, 8408A) An=(An-2)^2 + An-1 ; A1=2B) An= 3An-1 + 16; A1=16C) An= (n)An-1 - 8; A1=4D An=2An-2 + 7An-1; A1=2

Answer 1

When we substitute $n = 4$, we get...

$a_{n-3}=a_1\\ \\ a_{n-2}=a_2\\ \\ a_{n-1}=a_3\\ \\ a_n=a_4$

Comparing the given sequence: 24, 88, 664, 8408, we get

$a_{n-3}=a_1=24\\ \\ a_{n-2}=a_2=88\\ \\ a_{n-1}=a_3=664\\ \\ a_n=a_4=8408$

We need to substitute the above values in each option and check which is TRUE.

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Option A

$a_n=(a_{n-2})^2+a_{n-1}, a_1=2\\ \\ a_n=(88)^2+664=7744+664\\\\a_n=8408 (TRUE)$

Option B

$a_n=3a_{n-1}+16\\ \\ a_n=3(664)+16\\\\a_n=2008 (FALSE)$

Option C

$a_n=(n)a_{n-1}-8\\ \\ a_4=(4)a_3-8=4(664)-8\\\\a_4=2648 (FALSE)$

Option D

$a_n=2a_{n-2}+7a_{n-1}\\ \\ a_n=2(88)+7(664)\\ \\ a_n=4824(FALSE)$

Conclusion:

Option A is the correct answer.

Answer 2

Answer:

its a on edge

Step-by-step explanation: