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aliya0001 [1]
3 years ago
9

I need help with this problem asap

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0

════════ ∘◦❁◦∘ ════════

<h3>Answer</h3>

a = 36

b = √3/5

════════════════════

<h3>Known </h3>

Adjuscent = 12√3

════════════════════

<h3>Question</h3>

Opposite = ?

Hypotenuse = ?

════════════════════

<h3>Way to do</h3>

• finding a - opposite

#use tan formula

tan(∅) = opposite / adjuscent

tan(60) = opposite / 12√3

opposite = tan(60) × 12√3

opposite = 36

•finding b - hypotenuse

#use cos formula

cos(∅) = adjuscent / hypotenuse

cos(60) = 12√3 / hypotenuse

hypotenuse = 12√3 : cos(60)

hypotenuse = √3/5

════════════════════

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