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3 years ago

Which value for a completes the conditional relative

Mathematics

2 answers:

AveGali [126]3 years ago

8 0

Answer:

Option C.

Step-by-step explanation:

We need to find the value of a in the given conditional relative frequency table by row.

In a conditional relative frequency table by row, the sum of relative frequencies of a row is 1. So, we get

$a+0.9=1.0$

Subtract 0.9 from both sides.

$a+0.9-0.9=1.0-0.9$

$a=0.1$

The value of missing relative frequency is 0.1.

Hence the correct option is C.

Aleks [24]3 years ago

5 0

Answer:

The answer is C) 0.1

Step-by-step explanation:

The missing variable has to complete the table and equal 1.0, so you have to find which answer will fit that requirement. 0.9 + 0.1 = 1.0

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2 years ago

Y=3(x-2)+1 how can i graph this into slope intercept form

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2 years ago

Given f(x) = | – 5 – 4x| ,find the following:

jasenka [17]

Answer:

$f(10) = 35 \\ \\ f( - 11) = 39 \\ \\ f(12) = 53 \\ \\ f(2) = 13$

Step-by-step explanation:

$f(x) = | - 5 - 4x|$

To solve for the following substitute the value of x in the brackets into the above formula and solve for the value of x

NB:  Absolute value of a negative number is the same number but positive.

So we have

$f( - 10) = | - 5 - 4( - 10)| \\ = | - 5 + 40| = 35 \\ \\ f( - 11) = | - 5 - 4( - 11)| \\ = | - 5 + 44| = 39 \\ \\ f(12) = | - 5 - 4(12)| \\ = | - 5 - 48| \\ = | - 53| = 53 \\ \\ f(2) = | - 5 - 4(2)| \\ = | - 5 - 8| = | - 13| \\ = 13$

Hope this helps you

6 0

2 years ago

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Help me and I’ll give A Brainly star

Ilya [14]

Answer:

the answer was not found :(

Step-by-step explanation:

Merry Christmas and happy holidays!

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2 years ago

This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out

Dmitry [639]

Base be y

ATQ

$\\ \sf\longmapsto xy=6050\dots 1$

$\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2$

Now

$\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy$

$\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2$

$\\ \sf\longmapsto 12100-12100=x^2+y^2$

$\\ \sf\longmapsto x^2+y^2=0\dots(3)$

From all equations

$\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy$

$\\ \sf\longmapsto (x-y)^2=0-2(6050)$

$\\ \sf\longmapsto (x-y)^2=-12100$

$\\ \sf\longmapsto (x-y)=110\dots(4)$

Now

Adding 3 and 4

$\\ \sf\longmapsto 2x=220$

$\\ \sf\longmapsto x=110m$

One side won't be covered hence

y=2(110)=220m

7 0

2 years ago

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