All categories

3 years ago

An Italian restaurant buys 15 pounds of onions every 2 weeks. how many bags of onions will the restaurant buy in 7 weeks?

2 answers:

4 0

Since it is 7 weeks and they order 15 pounds every two weeks they will order 3 times. 15 times 3 is 45. Your answer is 3 bags

tresset_1 [31]3 years ago

4 0

2 goes into the 7 weeks 3 times with a remainder of a week until they buy another 15 pounds of onions. So 15 x 3 = 45 pounds. They’ll have 45 pounds of onions in 7 weeks as on the 8th week they’ll buy another 15 pounds but the question only wants to know by the 7th week.

You might be interested in

How do you find measures using postulates and theorems?

Dennis_Churaev [7]

Just use the definitions and put them in order to explain the problem.m. for instance. why are angles a and b vertical angles? they are adjacent and they are supplementary.

8 0

2 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

3 years ago

A farmer sold 54 pumpkins the first weekend of a fall festival and 42 pumpkins the second weekend. Which expression uses the dis

malfutka [58]

?-54-42=?
I hoped this helped

4 0

3 years ago

What is the measure of each exterior angle of a decagon?

NemiM [27]

The sum of all of the exterior angles of any regular polygon is 360 (I'm assuming by decagon you mean a regular dodecagon).

Because the total has to be 360, and a decagon has 10 sides, you divide 360 by 10 to get each exterior angle.

360 ÷ 10 = 36, so each exterior angle of a decagon is 36 degrees.

3 0

3 years ago

She's going to bake 12 batches of cookies. Each batch requires 1/8 cup of sugar. How many cups of sugar will grandma need for al

NikAS [45]

1.5 cups of sugar

>>

1/8 cup PER batch * 12 batches
(1/8)*12 = 1.5 cups

7 0

2 years ago