The expected value is just the weighted average of how much one ticket wins. To calculate it, we need to find the probabilities of winning each dollar amount, multiply each probability with it's respective dollar amount, then find the sum.
Let's call the winnings from one ticket X:
P(X=30) = 4000/2000000 = 0.002
P(X=800) = 500/2000000 = 0.00025
P(X=1200000) = 1/2000000 = 0.0000005
E(X) = 30*P(X=30) + 800*P(X=800) + 1200000*P(X=1200000) = 0.06 + 0.2 + 0.6 = 0.86
The answer is $0.86
Step-by-step explanation:
there is a (V.O.A) which is vertically opposite angle
and in the given part he himself said that there is two = angles
so there for the two third angles are equal
so we can say they are similar
Answer: 4
Step-by-step explanation: Divide 28 by 7
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Multiply sides by 5 / 13




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I believe the answer is cos^2 theta. Sec^2 theta on the right side of the equation is the inverse of Cos^2 theta, so multiplying the two together will get you 1. Cos^2 theta * Tan^2 theta = Sin^2 theta, and Cos^2 theta * 1 = Cos^2 theta. This all leads to the third and last step in the picture above.