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2 years ago

Help please !!!!!!!!!!

Mathematics

1 answer:

denis-greek [22]2 years ago

5 0

255 Is the correct answer

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What steps are involved in multiplying and dividing rational expressions?

zysi [14]

Answer:

Q and S do not equal 0.

Step 1: Factor both the numerator and the denominator. ...

Step 2: Write as one fraction. ...

Step 3: Simplify the rational expression. ...

Step 4: Multiply any remaining factors in the numerator and/or denominator. ...

Step-by-step explanation:

~Riley~

Have a Good day!

7 0

3 years ago

Read 2 more answers

Find the volume of each prism

o-na [289]

Volume of a prism=LWH
V=12 3/8 * 10*5
V=12.375 * 50
V=618.75
The volume of the prism is 618.75yd³

4 0

3 years ago

Lockheed Martin, the defense contractor designs and build communication satellite systems to be used by the U.S. military. Becau

Nana76 [90]

Answer:

$P(52$

And we can find this probability with this difference:

$P(-0.851$

And if we use the normal standard distribution or excel we got:

$P(-0.851$

Step-by-step explanation:

Let X the random variable that represent the time required to construct and test a particular component of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,9.4)$

Where $\mu=60$ and $\sigma=9.4$

We want to find this probability:

$P(52$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(52$

And we can find this probability with this difference:

$P(-0.851$

And if we use the normal standard distribution or excel we got:

$P(-0.851$

5 0

2 years ago

G varies directly with h and inversely with the square off. When h=16,f=2,

Rufina [12.5K]

Answer:

wefew

Step-by-step explanation:

awhefiuLLLESoagFVRESESGREGESRGSAERG$W$EG$%agwafer

6 0

2 years ago

For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is direct

Mrrafil [7]

THe problem is basically telling us: $P=kV^2$

where P is the power disappated and V^2 is our voltage squared.

$\frac{1}{16}=k*14^2\implies\\ \frac{1}{16*196}=k \implies \\ \frac{1}{3136}=k$

So, for the second example to find the power we simply have to plug k and our voltage back in, so: $P=\frac{14^2*3^2}{14^2*6} \implies \\ P=\frac{9}{6}= \frac{3}{2}$

6 0

3 years ago