If poaching reduces the population of an endangered animal by 6% and the criteria of population extinction is 20 with present population 1500 then it will take 3.62 years to reach to the mark of extinction.
Given Poaching reduces the population of endangered animals by 6% per year. The criteria of population extinction is 20. Present population being 1500.
Number of years taken by the population of endangered animals to reach to 20 mark can be calculated as under:
20=1500*
20=1500*
20/1500=
0.133=
take log both sides
log(0.133)=log
-------1
log(0.133)=nlog (0.94)
put the values log values:
log(0.133)=-0.8761
log(0.94)=-0.0268
Taking 1
-0.8761=n*(-0.0268)
n=0.8761/0.0268
n=3.269
Hence to reach level of 20 the population takes 3.2 years.
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Answer:
C 36
Step-by-step explanation:
When we have to exponents to the same base, and we are dividing them, we can subtract the exponents
a^b ÷ a^c = a^ (b-c)
6^7 ÷ 6^5 = 6^(7-5)
= 6^(2)
= 36
Hello from MrBillDoesMath!
Answer: b
Discussion:
7b + 3 - 4b = 3 - 3(b+4) =>
7b + 3 - 4b = 3 - 3b -12 =>
(7b - 4b) + 3 = -3b - 9 =>
3b + 3 = -3b -9 => Add 9 to both sides
3b + 12 = -3b -9 + 9 =>
3b + 12 = -3b => ( add 3b to both sides)
6b + 12 = 0 => (subtract 12 from both sides)
6b = -12 =>
b = -12/6 = -2
Thank you,
MrB
You’d do 16x5 and that would give you 80in^2 your welcome! Hope this helps!