Answer:
the dependent variable would be the growth of the plants
Explanation:
I know this because the independent variable is what changes which would be the amount of water and the dependent variable is what is being measured which is the growth of the plant
Answer:
A. 1.96 m/s.
B. 0.35 m.
C. 0.15 m.
Explanation:
A.
Velocity of a wave,v = f * lambda
Where,
f = frequency of the wave
Lambda = wavelength
Given:
T = 2.8 s
f = 1/T
= 1/2.8
= 0.36 hz
Lambda = 5.50 m
V = 5.5 * 0.36
= 1.96 m/s.
B.
Amplitude, a = distance/2
= 0.7/2
= 0.35 m.
C.
Amplitude, a = 0.3/2
= 0.15 m.
The magnitude of the work done to push the object is 90,000 J
<h3>
When is Work done on a body ?</h3>
Work is done on a body when the direction of the force applied is parallel to the direction of the displacement of the body.
The following parameters are given;
First convert the distance in kilometer to meter by multiplying it by 1000
S = 1.2 x 1000 = 1200 m
From the definition of work,
W = F x S
Substitute the parameters into the formula
W = 75 x 1200
W = 90,000 J
Therefore, the magnitude of the work done to push the object is 90,000 J
Learn more about Work here: brainly.com/question/25573309
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Hey there mate ;)
Given PPT image question is attached.
For answers :-
☆ The spectators in the stand are like particles in a <em><u>solid</u></em><em> </em>because <em><u>the</u></em><em><u> </u></em><em><u>spectators</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>sitting</u></em><em><u> </u></em><em><u>very</u></em><em><u> </u></em><em><u>close</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>no</u></em><em><u> </u></em><em><u>spaces</u></em><em><u> </u></em><em><u>in between</u></em><em><u> </u></em><em><u>them</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>solids</u></em><em><u>. </u></em>
☆ The players in the pitch are like particles in a <em><u>gas</u></em><em> </em>because <em><u>there</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>large</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>space</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>players</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>gases</u></em><em><u>.</u></em>
☆ The spectators standing in the terraces are like particles in a <em><u>liquid</u></em> because <em><u>there is </u></em><em><u>little</u></em><em><u> space in between the spectators, which is like a property of liquid.</u></em>
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
Know more about speed here:
brainly.com/question/19930939
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