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Alja [10]
3 years ago
10

If you push a 900N refrigerator with the same force as you lift a 40N dumbbell, the dumbbell will move faster. According to Chap

ter 12, which of Newton’s laws is this an example of? Explain how you know.
Physics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

Second Newton's law

Explanation:

Second Newton's law states that the acceleration of an object is related to the mass of an object and the force applied to it by:

F=ma

where

F is the net force applied to an object

m is the mass of the object

a is the acceleration

The equation can be rewritten also as

a=\frac{F}{m} (1)

we see that the acceleration is directly proportional to the force applied, F, and inversely proportional to the mass of the object, m.

In this problem, the force applied to the two objects (refrigerator and dumbbell) is the same, so we must look at their mass. Their mass can be found starting from their weight, which we know:

- refrigerator: m=\frac{W}{g}=\frac{900 N}{9.8 m/s^2}=91.8 kg

- dumbbell: m=\frac{W}{g}=\frac{40 N}{9.8 m/s^2}=4.1 kg

The dumbbell has a smaller mass, therefore by looking at formula (1), we can see that it will have more acceleration, and this is why it will move faster.

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The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
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Answer:

(a)255mm \\ (b)0.255m

Explanation:

(a)1cm = 10mm \\ 25.5cm = x

Cross multiply

1x = 25.5 \times 10 \\ x = 255mm

(b)100cm = 1m \\ 25.5cm = x

cross multiply

100x = 25.5 \\  \frac{100x}{100}  =  \frac{25.5}{100}  \\ x = 0.255m

hope this helps

brainliest appreciated

good luck! have a nice day!

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A student is swimming south applying a force of 256 N. The water exerts a westward force of 104 N. If the student has a mass of
grigory [225]

Answer:

a=2.9\ m/sec^2

Explanation:

<u>Net Forces and Acceleration</u>

The second Newton's Law relates the net force F_r acting on an object of mass m with the acceleration a it gets. Both the net force and the acceleration are vector and have the same direction because they are proportional to each other.

\vec F_r=m\vec a

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

The magnitude of the resulting force F_r is computed as the hypotenuse of a right triangle

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|F_r|=276.32\ Nw

The acceleration can be obtained from the formula

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\boxed{a=2.9\ m/sec^2}

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