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Eva8 [605]
3 years ago
8

Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are rando

mly​ selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not​ work?
Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0
1) 11-3= 8 TV work
8/11 - probability 1st TV works
7/10 -probability 2nd TV works
8/11*7/10=28/55 that both TV work

2)3/11 first TV does not work       
8/10 second TV works
3/11*8/10 = 12/55 that at least one does not work

ahrayia [7]3 years ago
4 0
Hello!

You have to first find the percentage of the tv's are defective

3/11 = 0.27

27% of the tvs are defective

the probability of one of the tv's working is 8/11

the probability of the second tv working is 7/10

You multiply these together

8/11 * 7/10 = 28/55

There is a 28 out of 55 chance both tvs work

There is a 3/11 probability that one of the tvs does not work

Hope this helps!
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(0,0) and (7,10)

Step-by-step explanation:

recall that the slope - intercept  form of a linear equation can be given as

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since we are not given any information about the y-intercept, we can simply pick a value for b that is most convenient for us.

We pick b = 0, hence the equation simplifies to:

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we can see immediately that if x = 0, y must also = 0

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since 0 is an integer, then (0,0) must be the first point.

we can also observe that for y to be an integer, we must get rid of the denominator 7. We can do this by multiply the right side by 7. Hence we let x = 7:

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7 0
4 years ago
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Nataliya [291]

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3 0
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3 years ago
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