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attashe74 [19]
3 years ago
6

Statements :

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

"e^x is irrational for every nonzero integer x"

Step-by-step explanation:

The original statement is

"e^x is rational for some nonzero integer x."

The negation is technically:

"It is NOT true that e^x is rational for some nonzero integer x."

So it's expressing that it's false that e^x can be rational for some nonzero integer x.

This just means that e^x is always irrational when x is a nonzero integer.

Which can be worded as

"e^x is irrational for every nonzero integer x"

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