Question

Statements :

Answer 1

Answer:

"$e^x$ is irrational for every nonzero integer x"

Step-by-step explanation:

The original statement is

"$e^x$ is rational for some nonzero integer x."

The negation is technically:

"It is NOT true that $e^x$ is rational for some nonzero integer x."

So it's expressing that it's false that $e^x$ can be rational for some nonzero integer x.

This just means that $e^x$ is always irrational when x is a nonzero integer.

Which can be worded as

"$e^x$ is irrational for every nonzero integer x"