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3 years ago

WILL GIVE BRAINLIST ive seen this problem so many times and I've tried my best to solve it but I really need some help here

Mathematics

2 answers:

allsm [11]3 years ago

8 0

Answer:

Let O be the center of the circle.

<COA = 90*

<FOE = <AOB = 146*

Considering that a circle is 360* we have <BOC = 124*

The Arc ABC is <AOB + <BOC = 124 + 90 =214*.

larisa [96]3 years ago

8 0

Answer:

m ABC = 270°

Step-by-step explanation:

Note that the measure of the circle = 360°

m CA = 90°, thus

m ABC = 360° - m CA = 360° - 90° = 270°

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What is the answer to this equation ... 3 + 2c + 5c + 2 ??

Lilit [14]

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3 years ago

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PLEASE HELP!! Find the equation of the line that is perpendicular to y= -2/3x and contains the point (4,-8).

AlladinOne [14]

Answer:

y = 3x/2 +14

Step-by-step explanation:

gradient = -2/3

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2 years ago

7x +2y = 24<br> 8x+2y= 30<br> What is x and y

Liula [17]

Answer:

x = 6

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Step-by-step explanation:

we have:

7x +2y = 24 equation 1

8x+2y= 30 equation 2

using equation 2 we have:

8x = 30 -2y

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using equation 3 in equation 1 we have:

7( $\frac{30-2y}{8}$ )+2y = 24

$\frac{210}{8} - \frac{14y}{8} +2y =24\\\\\frac{1}{4}y = -\frac{18}{8} \\\\y=-\frac{18}{8} * 4\\\\y=-9$

so we have:

x= $\frac{30-2(-9)}{8}$

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3 years ago

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Andre45 [30]

Answer:

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3 years ago

Find a cubic function with the given zeros. (1 point) Square root of seven. , - Square root of seven. , -4

Debora [2.8K]

Given :

Three roots , $\sqrt{7},\ -\sqrt{7},\ -4$ .

To Find :

A cubic function with the given zeros.

Solution :

Equation of polynomial of 3 zeroes is given by :

$(x-a_1)(x-a_2)(x-a_3)=0\\\\(x-\sqrt{7})(x+\sqrt{7})(x+4)=0\\\\( x^2-7)(x+4)=0\\\\x^3+4x^2-7x-28=0$

Therefore, the cubic function of given zeroes is $x^3+4x^2-7x-28=0$ .

Hence, this is the required solution.

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3 years ago