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evablogger [386]
3 years ago
15

You plant a regular garden that is your 7.5 feet wide and has an area of 78.75 square feet. You have 10 yards of wire fencing. D

o you have enough wire fencing to enclose the garden? Please should work
Mathematics
1 answer:
nevsk [136]3 years ago
8 0

Answer:

Therefore,

We do not have  enough wire  for fencing to enclose the garden,

that means  10 yards of wire is not enough.

We require 12 yards of wire for fencing.

Step-by-step explanation:

Given:

Let "L" and "W" be the Length and Width of the Rectangular Garden such that,

Width = W = 7.5 feet,

Area of Garden = 78.75 square feet

Total wire for fencing is 10 yards given

1 yard = 3 feet

therefore 10 yard = 30 feet  wire is there for fencing

To Find:

Total wire require for fencing = ?

Solution:

Area of Rectangle is given by

\textrm{Area of Rectangle}=Length\times Width

Substituting the values we get

78.75=Length\times 7.5\\\\Length=\dfrac{78.75}{7.5}=10.5\ feet

Now for fencing of the garden it will require to cover the whole rectangular shape garden so the total wire required for the fencing will be the perimeter of rectangle,

Now Perimeter of rectangle is given by,

\textrm{Perimeter of rectangle}=2(Length+Width)

Substituting the values we get

\textrm{Perimeter of rectangle}=2(10.5+7.5)=36\ feet

1 yard = 3 feet

Therefore, 36\ feet =\dfrac{36}{3}= 12\ yards

Therefore,

We do not have  enough wire  for fencing to enclose the garden,

that means  10 yards of wire is not enough.

We require 12 yards of wire for fencing.

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Answer:

Step-by-step explanation:

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Now we have to worry about the y intercept. When x = 0, y = 4. That can be accomplished in two ways

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The value of A will give y = 4/(5 + 1)=4/6 = 2/3. Which does not work.

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Only B works. y = 2/(5+1) + 2 = 2/6 + 2 = 2 1/3 which is a little above the horizontal asymptote.

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7 0
3 years ago
What is the area of a flower pot that have the shape of a semi circle and its diameter 2.8cm?​
Firdavs [7]

Step-by-step explanation:

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The diameter = 2.8 cm

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r = 2.8/2

r = 1.4

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The area of the circle = 3.14 * 1.4^2

The area of the circle = 6.1544

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The area of a semicircle is 1/2 that of a circle

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A triangle is shown. The table names different transformations that can be applied to the triangle.
Citrus2011 [14]

The given transformations are rigid transformation in which the image

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Response:

First reflect across the x-axis then reflect across the y-axis

  • Figure: Second graph

First, rotate 180° counterclockwise around the origin. Then reflect across the x-axis.

  • Figure: Third graph

First translate 9 units to the left. Then reflect across the x-axis

  • Figure: First graph

<h3>Which method is used to determine the transformation of an image?</h3>

The coordinates of (x, y) following a reflection across the x-axis is (x, -y)

The coordinates following a reflection across the y-axis is (-x, y)

The points of the triangle following the first transformation is therefore;

(4, 4) → (4, -4) → (-4, -4)

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The image from the second transformation is (-4, 4), (-8, 4), (-6, 6), which corresponds to the <u>third graph</u>.

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The image from the third transformation is (-13, -9), (-1, -4), (-7, -6), which corresponds to the<u> first graph</u>.

Learn more about rigid transformations here:

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