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3 years ago

What is the length of segment AE?

Mathematics

1 answer:

DedPeter [7]3 years ago

7 0

By looking at the bottom length of both triangles, we can determine the scale from one to the other.

C-E = 30 units
D-F = 28 units

This can be translated as the fraction 15/14.

So if we look back at the possible answers, both B and C are likely candidates for being the answer.

But to get the answer, we multiply 24 X (15/14).

Which is 25.7, or 25 and 5/7. Your answer is C.

You might be interested in

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago

You wish to take a flight from Nevada to New York. Use the point (-4, 0) to represent Nevada, and the (5, 2) to represent New Yo

mojhsa [17]

Using proportions, it is found that the ordered pair that represents the location of the layover is (3.75, 1.5).

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The flight distance is partitioned in a ratio of 3:1, hence, for both the x and y coordinates, we have that:

L - Nv = 3/4(Ny - Nv)

For the x-coordinate, we have that:

$x + 4 = \frac{3}{4}(5 + 4)$

$x = \frac{27}{4} - \frac{16}{4}$

$x = \frac{11}{4}$

x = 3.75

For the y-coordinate, we have that:

$y = \frac{3}{4}(2)$

$y = \frac{6}{4}$

y = 1.5.

The ordered pair that represents the location of the layover is (3.75, 1.5).

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

7 0

1 year ago

Please solve this quadratic equation:<br>3^2x -9 =0

Basile [38]

Answer:

${3}^{2} x - 9 = 0 \\ 9x = 9 \\ x = 1$

4 0

2 years ago

X^2-x-42=<br><br><br><br> factor as the product of two binomials

azamat

I’m pretty sure it’s (x-7)(x+6)

to factor you need it to multiply to -42 and add to -1 which gives you -7 and 6

5 0

2 years ago

Find the slope of the line graphed A) -1/2 ,B) -2, C) 1/2 D) 2

qaws [65]

Answer:

Step-by-step explanation:

3 0

2 years ago