Answer: Mabye like an ocean with dolphins swiming/jumping? Or even use the blue as a sky and then put green grass and do foxes or and a phoenix flying with a fox under it?
Explanation:
Just some ideas!
One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.
From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.
By equilibrium the centrifugal force and the gravitational force are equal therefore


Where
m = mass spacecraft
v = velocity
G = Gravitational Universal Constant
M = Mass of earth
Radius of earth and orbit
Re-arrange to find the velocity





Replacing with our values we have


From the cinematic equations of motion we have to
Remember that the speed is double for the counter-direction of the trajectories.
Replacing


Therefore the time required is 3.778s
Answer:
Mass of raft=m1= 1000kg
Mass of paddle=m2=40kg
Speed of paddle=v2=3 m/s
Speed of raft=recoil speed=v1=?
Formula
V1= -(m2/m1)v2= -(40/1000)3= - 0.12m/s
Explanation:
Here the raft has much greater mass as compare the paddle and its velocity will always be negative due to recoil. 1 and 2 with masses and velocities are subscripts.
Answer:
The second one
Explanation:
It caused both to change speed because they have both the same mass.
Answer:
9) This is a case of deceleration
10)-0.8 ms-2
b) acceleration is the change in velocity with time
11)
a) 100 ms-1
b) 100 seconds
12) 10ms-1
13) more information is needed to answer the question
14) - 0.4 ms^-2
15) 0.8 ms^-2
Explanation:
The deceleration is;
v-u/t
v= final velocity
u= initial velocity
t= time taken
20-60/50 =- 40/50= -0.8 ms-2
11)
Since it starts from rest, u=0 hence
v= u + at
v= 10 ×10
v= 100 ms-1
b)
v= u + at but u=0
1000 = 10 t
t= 1000/10
t= 100 seconds
12) since the sprinter must have started from rest, u= 0
v= u + at
v= 5 × 2
v= 10ms-1
14)
v- u/t
10 - 20/ 25
10/25
=- 0.4 ms^-2
15)
a=v-u/t
From rest, u=0
8 - 0/10
a= 8/10
a= 0.8 ms^-2