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OLga [1]
2 years ago
14

You and your friend are pushes hard against a stationary wall. If you push 3 times harder than your friend, then the amount of w

ork you do is
Physics
1 answer:
shtirl [24]2 years ago
5 0

Answer:

Work = F * s    where s is the distance F moves

Since F is stationary, in this case, "no work" is done by either person

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How much power does it take to lift a 30.0 n box 10.0 m high in 5.00 s, if you must apply a 62n force to lift the box?
Illusion [34]
Power is defined as the rate at which the body is doing work:
P=\frac{W}{t}
Work is defined as displacement done by the force times that displacement:
W=F\cdot h
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
W=62N\cdot10m=620J
of work.
Now we just divide that by 5s to get how much power is required:
P=\frac{620J}{5s}=124W
5 0
3 years ago
A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l
Shalnov [3]
Speed uses distance and velocity uses displacement in its calculation.

For 100 m race, distance = displacement. Hence speed = velocity

For 400m race, distance ≠ displacement. distance = 400m whereas displacement = 0m. Hence speed ≠ velocity
3 0
3 years ago
Read 2 more answers
Physics question, answer completely with work
Alenkasestr [34]

The force is 2.0 N east

Explanation:

The impulse exerted by a force is defined as the product between the force itself and the time interval during which the force is applied. Mathematically, it is equal to the change in momentum experienced by the object on which the force is acting:

I=F\Delta t = \Delta p

Where

I is the impulse

F is the force

Delta t is the time interval during which the force is applied

\Delta p is the change in momentum

In this problem,

\Delta t = 3.0 s is the time interval

I=6.0 N\cdot s (east) is the impulse

Therefore, the magnitude of the force is

F=\frac{I}{\Delta t}=\frac{6.0}{3.0}=2.0 N

And the direction is the same as the impulse (east).

Learn more about impulse and change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
In a real world trampoline, how do gymnasts keep a constant bounce height
kkurt [141]
By using common factors of physics: weight, gravity, and stability. 
Weight would keep them at a constant height.
Gravity helps the weight and how much force it propels the person, or objects, into the air.
Stability helps adjust how much distance the person, or object, needs to be.
7 0
3 years ago
TRANSFORMA: 765 mm Hg a atm
-Dominant- [34]

Presión

765

=

ATMÓSFERA

1,00658

Answer:

Explanation:

5 0
3 years ago
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