Answer:
Explanation:
500 MW = 500 X 10⁶ J / s
If R be the rate of heat supplied and 35 % is the efficiency of conversion
R x .35 = 500 X 10⁶
R = 500 X 10⁶ / .35
= 1428.57 x 10⁶ J / s
b )
Rate of heat going waste
= .65 x 1428.57 x 10⁶
= 928 .57 x 10⁶ J / s
c )
Heat content of coal = 30 x 10⁶ J /kg
1428.57 x 10⁶ J of heat will come from
= 1428.57 x 10⁶ J / 30 x 10⁶ J /kg
= 47.62 kg per second
= 47.62 x 24 x 60 x 60 = 4114368 kg in one day
= 4114368 / 907.185 ton per day
= 4535.31 ton per day
d ) Fuel consumption rate will decrease by 12.5 % if thermal efficiency is increased to 40 % .
The last one, at the bottom, is false.
<span>Since a watermill is powered by a water wheel the strength of the current and volume of the water passing the mill may alter the amount of power provided. Seasonal and climatic changes could contribute to changes in the current.</span>
Answer:
Lifetime = 4.928 x 10^-32 s
Explanation:
(1 / v2 – 1 / c2) x2 = T2
T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225
T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6
T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s
Answer:
1 or 2 or 3
Explanation:
it depends whether the coat is a light or dark colour. if it is lighly coloured it will not absorb heat from the sun and wont melt the snowman. if it is darkly coloured it will be number 1
the coat wont make a difference if the temperature of the snowman is the same and the temperature outside the snoman and the sun isnt shining. the coat would just make him look smart - so number 2
it coul keep in the cold and block out the warmth so number 3
