During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc
1 answer:
You might be interested in
Answer:
v = 54.2 m / s
Explanation:
Let's use energy conservation for this problem.
Starting point Higher
Em₀ = U = m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ 2gh
Let's calculate
v = √ (2 9.8 150)
v = 54.2 m / s
Answer:
3565 J
Explanation:
F = Force applied = 1550 N
s = Displacement caused by the applied force = 2.3 m
= Angle at which the force is applied = 0°
When we multiply force, displacement and the angle at which the force is applied we get work
Work done is given by
The work done by team A is 3565 J