You're looking for the extreme values of 
subject to the constraint 
.
The target function has partial derivatives (set equal to 0)
so there is only one critical point at 
. But this point does not fall in the region . There are no extreme values in the region of interest, so we check the boundary.
Parameterize the boundary of by
with 
. Then 
can be considered a function of 
alone:
has critical points where 
:
but 
for all , so this case yields nothing important.
At these critical points, we have temperatures of
so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.
I hope this helps you
[2×4+1/4]×(-8)
[8+1/4]×(-8)
9×-8/4
9×-2
-18
Answer: M(2) = $1500*(1 - 0.026)^2 = $1423.01
Step-by-step explanation:
Initially in the acount there is $1500
You lose a 2.6% (or 0.026 in decimal form) per year, so after the first year you have:
M = $1500 - 0.026*$1500 = $1461
After other year, you lose oter 2.6%
M = $1461 - 0.026*$1461 = $1423.01
The equation can be writen as:
M(t) = $1500*(1 - 0.026)^t
Where t is the number of years, you can use t = 2 and get:
M(2) = $1500*(1 - 0.026)^2 = $1423.01
Answer:
Equation: 
Solve for n: n = 112
Step-by-step explanation:
To first set up the equation, you need to look at the verbal description and translate into numbers and operations:
'three fourths a number' = 
'plus 8' = + 8
'is' =
'20 less' = - 20
'the number' = n
Put the expressions together:
'three fourths a number plus 8': 
'20 less than the number': n - 20
Set them equal to each other and solve:
Add 20 to both sides: 
Subtract 
from both sides: 
Multiply both sides by 
: 
Solve for n: n = 112
But, the y intercept is 2.
