The required simplified value of B - A = -6.
<h3>What is simplification?</h3>
The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.
Since, line Ax + By = 3 and x + 3y = -5 are parallel than slope of both the line will be same,
m = -1/3 = -A/B
From above
A = B/3 - - - - -(1)
Now line Ax + By = 3 passed through the point (-7, 2). So,
-7A + 2B = 3
from equation 1
-7B/3 + 2B = 3
-B/3 = 3
B = -9
Now put B in equation 1
A = -9 / 3
A = -3
Here,
B - A = -9 + 3 = -6
Thus, the required simplified value of B - A = -6.
Learn more about simplification here: brainly.com/question/12501526
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Answer:
59 F
Step-by-step explanation:
F=1.8C+32
Let C = 15
F = 1.8 (15) +32
Multiply 1.8 times 15
F = 27+32
F = 59
15 degrees C is 59 degrees F
Answer:
a. 60 centimeters
b. 67 centimeters
Step-by-step explanation:
a.
12 × 4 = 48
(6 × 4) ÷ 2 = 12
48 + 12 = 60
b.
7 × 10 = 70
(2 × 3) ÷ 2 = 3
70 - 3 = 67
B. is the answer because he can just refill the 1 gallon jug to eventually measure out 3 gallons!
Answer:
Therefore, the volume of the cone is V=4π.
Step-by-step explanation:
From task we have a circular cone with radius 2 m and height 3 m. We use the disk method to find the volume of this cone.
We have the formula:
We know that r=2 and h=3, and we get:
![V=\int_0^3\pi \cdot \left(\frac{2}{3}x\right)^2\, dx\\\\V=\int_0^3 \pi \frac{4}{9}x^2\, dx\\\\V= \frac{4\pi}{9} \int_0^3 x^2\, dx\\\\V= \frac{4\pi}{9} \left[\frac{x^3}{3}\right]_0^3\, dx\\\\V= \frac{4\pi}{9}\cdot 9\\\\V=4\pi](https://tex.z-dn.net/?f=V%3D%5Cint_0%5E3%5Cpi%20%5Ccdot%20%5Cleft%28%5Cfrac%7B2%7D%7B3%7Dx%5Cright%29%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%5Cint_0%5E3%20%5Cpi%20%5Cfrac%7B4%7D%7B9%7Dx%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cint_0%5E3%20x%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D_0%5E3%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5Ccdot%209%5C%5C%5C%5CV%3D4%5Cpi)
Therefore, the volume of the cone is V=4π.
