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Anuta_ua [19.1K]
3 years ago
7

Expressed in simplified radical form what is the value of √r-√16r when r=2

Mathematics
1 answer:
Ket [755]3 years ago
5 0

Answer:

- 3\sqrt{2}

Step-by-step explanation:

using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

simplifying \sqrt{16r} when r = 2

= \sqrt{32}

= \sqrt{16(2)}

= \sqrt{16} × \sqrt{2} = 4\sqrt{2}, hence

\sqrt{2} - 4\sqrt{2} = - 3\sqrt{2}


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