Question

Expressed in simplified radical form what is the value of √r-√16r when r=2

Answer 1

Answer:

- 3$\sqrt{2}$

Step-by-step explanation:

using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

simplifying $\sqrt{16r}$ when r = 2

= $\sqrt{32}$

= $\sqrt{16(2)}$

= $\sqrt{16}$ × $\sqrt{2}$ = 4$\sqrt{2}$, hence

$\sqrt{2}$ - 4$\sqrt{2}$ = - 3$\sqrt{2}$