I'll make you brainlist and 40 points (2z²)^-3please hurry

Mathematics

2 answers:

gladu [14]3 years ago

7 0

Is the goal to simplify? You just need to multiply the exponents for each factor:

(2z^2)^(-3)
= 2^(-3) x z^(2 x -3)
= (1/2)^3 x z^(-6)
= (1/8) x (1/z)^6
= 1/(8z^6)

Sindrei [870]3 years ago

6 0

Answer:

(2z^2)^(-3)

= 2^(-3) x z^(2 x -3)

= (1/2)^3 x z^(-6)

= (1/8) x (1/z)^6

= 1/(8z^6)

please brainliest

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

Please help, I’ll mark your answer as brainliest!

statuscvo [17]

Answer:

$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .