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Troyanec [42]
3 years ago
6

I'll make you brainlist and 40 points (2z²)^-3please hurry​

Mathematics
2 answers:
gladu [14]3 years ago
7 0
Is the goal to simplify? You just need to multiply the exponents for each factor:

(2z^2)^(-3)
= 2^(-3) x z^(2 x -3)
= (1/2)^3 x z^(-6)
= (1/8) x (1/z)^6
= 1/(8z^6)
Sindrei [870]3 years ago
6 0

Answer:

(2z^2)^(-3)

= 2^(-3) x z^(2 x -3)

= (1/2)^3 x z^(-6)

= (1/8) x (1/z)^6

= 1/(8z^6)

please brainliest

Step-by-step explanation:

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A + b = 10 a - b = 2
Aliun [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
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2x +4=12 step by step
Alekssandra [29.7K]

x=4

Step-by-step explanation:

2x+4=12

-4 -4

---------------

2x = 8

---- ---

2 2

x=4

6 0
3 years ago
I would like to know the result of 3^3
galina1969 [7]

Answer:

3^{3} = 27.

Step-by-step explanation:

3 to the third power ( 3^{3} ) is the same as :

3 x 3 x 3 which would equal :

3 x 3 = 9 x 3 = 27.

Hope this helps,

Davinia.

5 0
3 years ago
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Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid
Gnom [1K]

Answer:

The area of the triangle is A=\sqrt{\frac{4027}{2}}

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

A=\frac{1}{2}||{\bf u} \times {\bf v} ||

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

{\bf AB} and {\bf AC}

The vector {\bf AB} is the difference of point B minus point A

{\bf AB}=(5-3,5-5,0-9)=(2,0,-9)

and the vector {\bf AC} is the difference of point C minus point A

{\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)

Next we need to find the cross product of this vectors.

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

This is the definition of cross product of two vectors in space:

Let {\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k} and {\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k} be vectors in space. The cross product of {\bf u} and {\bf v} is the vector

{\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}

Applying this definition we get

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}

||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}

The area of the triangle is

A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}

7 0
4 years ago
W + 7/w - 2 = w + 7/w-1 + 1<br>​
Reptile [31]

Answer:

Step-by-step explanation:

sbsjbjbdcjbjbdyiy

3 0
3 years ago
Read 2 more answers
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