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hodyreva [135]
3 years ago
9

Show your work 7(x-8)=2x-31

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

x=5

Step-by-step explanation:

7 (x-8)=2x-31

Distribute the 7 to the x and -8 (basically multiple 7 with the x and -8)

7x-56=2x -31

Drag the 2x over to the other subtracting it from 7x.

7x-2x-56=-31

5x-56=-31

Drag the 56 to the other side and add it to -31

5x= -31+56 (or 56-31)

5x= 25

Divide 5x from 25 to get your X

x=25/5

x=5

Hope this helps!!

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You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk
ra1l [238]

Volume is a measure of the <u>quantity </u>of <em>substance</em> a given <u>object</u> can contain. The required answers are:

1.1  The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2  The area of <em>cardboard</em> required to make a single <u>milk</u> carton is  332.6 cm^{2}.

1.3  Each <u>carton</u> can hold 0.36 liters of <u>milk</u>.

1.4  The <em>cost</em> of filling the 200 <u>cartons</u> is R 86.40.

The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

The <u>area</u> of a given <u>shape</u> is the amount of <em>space</em> that it would cover on a 2-dimensional <em>plane</em>. Examples of <u>shapes</u> to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a <u>cuboid</u>. So that;

<u>Volume</u> of <u>cuboid</u> = length x width x height

Thus,

1.1 The <u>volume</u> of each <u>milk</u> carton = length x width x height

                                                         = 6 x 6 x 10

                                                        = 360

The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

                                                    = 6 x 10

                                                    = 60

Total <u>area</u> of the <u>rectangular</u> surfaces = 4 x 60

                                                     = 240 cm^{2}

ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

                                                   = 6 x 6  

 <u>Area</u> of the <u>square</u> surface = 36 cm^{2}

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = \pi r^{2}

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 \pi r^{2}

                                        = 2 x \frac{22}{7} x (3)^{2}

                                        = 56.57

Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 cm^{2}

Therefore, total area of  <em>cardboard</em> required = 240 + 36 + 56.6

                                                            = 332.6 cm^{2}

The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is  332.6 cm^{2}.

1.3 Since,

  1 cm^{3}  = 0.001 Liter

Then,

360 cm^{3} = x

x = 360 x  0.001

  = 0.36 Liters

Thus each<em> carton</em> can hold 0.36 liters of <u>milk</u>.

1.4 total cartons = 200

<em>Total volume</em> of <u>milk </u>required = 200 x 0.36

                                                 = 72 litres

But, 1 kiloliter costs R1 200. Thus

<em>Total volume</em> in kiloliters = \frac{72}{1000}

                                         = 0.072 kiloliters

The <u>cost</u> of filling the 200 cartons = R1200 x 0.072

                                         = R 86.40

The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

#SPJ1

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