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snow_tiger [21]
3 years ago
15

ΔACB • ΔEFD

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

y=4

Step-by-step explanation:

You might be interested in
What is between 3/8 in a number line
storchak [24]
Okay I hope this is what you mean. so if you are saying what is between the numbers 3 and 8 we can make an inequality which will cover all the small decimals between the numbers.

There are 2 different equalities that I'm not sure which one you want.

so the first one would be
3 \leqslant x \leqslant 8
x is just the variable I chose for this. Now this inequality means that both 3 and 8 are solutions to the problem. x represent all the little numbers in between so to test your answers just plugin the number you're testing in for x. Since 3 is the lowest number it will have a less than or equal to (in this case) sign and 8 is the greatest so that's why the open/greater side is facing the 8. It reads 3 is less than or equal to x and x is less than or equal to 8.

If you meant all number in between 3 and 8 not include either of those numbers than the inequality would be
3 < x < 8
In this case all the numbers between 3 and 8 are solutions but 3 and 8 will not be solutions. the line under the symbol means it includes the number which come before or after it. The inequality reads 3 is less than x which is less than 8. You can also plugin in an answer to test it in place of x.


If you have any questions or it turns out you meant somthing else please tell me and I'll be happy to help, sorry if this isn't what you meant in the question.
3 0
3 years ago
How do you do this? Distributive property plz help (num 3)
Advocard [28]
-9-(12-3x)=-9-1*(12)-1*(-3)=-9-12+3x=-21+3x=3(x-7)
4 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
Solve for x <br><br>x- 5/3=1​
Tasya [4]

Answer:

x = 8/3 or 2 2/3

Step-by-step explanation:

x - 5/3 = 1

x - 5/3 + 5/3 = x

1 + 5/3 = 8/3 or 2 2/3

x = 8/3 or 2 2/3

4 0
3 years ago
Read 2 more answers
he puppy weighed 2 pounds when it was born. He has gained weight, but still weighs less than 11 pounds. How much weight could he
Vikentia [17]

Answer:

n=9

Step-by-step explanation:

just did it

4 0
3 years ago
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