No, it is not. If you plug 4 into the equation in the place of x, you get 13=2(4)+4
13=8+4
13=12
It equals 12, not 13.
True us the answer too your question.
X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Answer:
c. quadrilateral
Step-by-step explanation:
All of the sides are different lengths, so the quadrilateral cannot be a parallelogram, rhombus, or square.
Its best descriptor is <em>parallelogram</em>.
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A <em>parallelogram</em> has opposite sides parallel and congruent. A <em>rhombus</em> also has adjacent sides congruent. A <em>square</em> is a special case of rhombus in which the corner angles are right angles.
Answer:
(x-8)/10
Step-by-step explanation:
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