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ziro4ka [17]
3 years ago
15

What air mass would produce cold, dry weather in the winter

Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0

The air mass that would produce cold, dry weather in the winter is called Continental Polar.

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8 0
3 years ago
A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

x' = +6-6

x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

5 0
3 years ago
An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos
disa [49]

The sign associated with the average velocity of the object is negative.

<h3>Average velocity of the object</h3>

The average velocity of the object is calculated as follows;

Average velocity = (v1 + v2)/2

v1 = -20/30 = -0.667 m/s

v2 = 20/50 = 0.4 m/s

Average velocity = (-0.667 + 0.4)/2

Average velocity  = -0.134 m/s

Thus, the sign associated with the average velocity of the object is negative.

Learn more about average velocity here: brainly.com/question/6504879

#SPJ1

7 0
2 years ago
Discuss the circular nature of the rides and how centripetal force plays a role.
Mars2501 [29]

see attached ... heart = a person

3 0
3 years ago
A horizontal pipe narrows from a radius of 0.250 m to 0.1000 m. If the speed of the water in the pipe is 1.00 m/s in the larger-
umka21 [38]

Answer:

6.25 m/s

196 kg/s

Explanation:

The areas of the pipe from big to small:

A = \pi R^2 = \pi*0.25^2 = 0.196 m^2

a = \pi r^2 = \pi*0.1^2=0.0314m^2

As the product of speed and cross-section area is constant, the speed in the smaller pipe would be

AV = av

v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s

The mass flow rate would be:

\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s

4 0
3 years ago
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