Current flow depends on other things in addition to the circuit configuration.
If the SAME voltage is applied to some arrangement of the SAME components, the greatest current will occur when they are all in parallel.
Answer:
A. The wavelengths of the new sound waves are longer
Explanation:
This is the Doppler effect which can be best illustraded for the case of a siren of an ambulance approaching us having a greater frequency and getting lower in frequency and deeper as the ambulance passes us.
Since the wavelength is inversely proportional to the frequency it follows the wavelengths are longer when the frequency decreases lowering its pitch and getting deeper.
Answer:
Yes is large enough
Explanation:
We need to apply the second Newton's Law to find the solution.
We know that,

And we know as well that

Replacing the aceleration value in the equation force we have,

Substituting our values we have,


The weight of the person is then,


<em>We can conclude that force on the ball is large to lift the ball</em>
Answer with Explanation:
We are given that
Mass of spring,m=3 kg
Distance moved by object,d=0.6 m
Spring constant,k=210N/m
Height,h=1.5 m
a.Work done to compress the spring initially=
b.
By conservation law of energy
Initial energy of spring=Kinetic energy of object



v=5.02 m/s
c.Work done by friction on the incline,
