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3 years ago

Which of the following is a solution for |x – 6| < 4?

1 answer:

7 0

D. x=4 <span>|4 – 6| < 4 = -2 but since anything inside an absolute value sign has to be positive it becomes 2<4.
</span>
The others become:
9<4
4<4
5<4
all of which are not true

Hope that helps

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Multiply. Write the answer in simplest form.<br> 1/2 x 3/5 x 4/9

dexar [7]

Answer:

4/75

Step-by-step explanation:

5 0

3 years ago

Erica measures the mass of a steel ball several different times. If Erica's results are highly precise, this must mean that A. m

Delvig [45]

C, her results are very close to one another

8 0

3 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

mr stephens needs to haul 1,518 tons of rocks from a construction site. His dump truck can hold 26 ton per load. how many tons w

lisov135 [29]

Answer:

Step-by-step explanation:

1518 divided by 26 is 58 remainder 10.

... 1518 = 26×58 + 10 = 1508 + 10

Mr. Stephens will make 58 trips with a full load. After that, 10 tons of rock will remain.

6 0

3 years ago

X = 2y + 3<br> X = 3y -4

iren2701 [21]

Answer: Let F(x, y, z) = x 2y 3 i+x 3y 2 j+ 2zk and C the curve parameterized by x(t) = cost, y(t) = sin t, and z(t) = t 2π

Step-by-step explanation:

8 0

3 years ago