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Maurinko [17]
3 years ago
7

The sum of three consecutive even numbers is 582. What is the 1st number?

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

d

Step-by-step explanation:

y

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In circle T with m∠STU=78 and ST=8 , find the length of arc SU. Round to the nearest hundredth.
evablogger [386]

Answer:

10.89

Step-by-step explanation:

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3 years ago
A triangle with vertices (0, 4), (3, 7) and (5, 1) is translated a distance of 4 units to the left. What are the new coordinates
STALIN [3.7K]
The new coords are (-4, 4), (-1,7) and (1,1)
5 0
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PLEASE HELP I ONLY HAVE TODAY TO DO THIS PLEASE
balandron [24]

Answer:

6

Step-by-step explanation:

this should br what it looks like

6 0
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Which one is the correct one please
yan [13]

Answer:

The answer is 41

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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
2 years ago
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