y=3x^3-2x, dx/dy =3
dy/dt= ? (when x=-2)
dy/dt= d/dt (3x^3 -2x)
= 9x^2(dx/dt) -2(dx/dt)
= 9(-2)^2 * 3 - (2*3)
= 9(4)*3 -6
= 102
Answer:
17
Step-by-step explanation:
3 multiply by 5 (which is x) = 15+2
.5
5 hours
39 - 14 = 25
5 x 5 = 25
14 + 25 = 39
{1,6}
the second box is always where the y values/range are